Find the minimal and maximal number of vertices in a balanced tree of height n.
The maximal number of vertices is equal to 2^{n+1} – 1. If m_n is the minimal number of vertices, then m_{n+2} = 1 +m_n + m_{n+1}. An easy induction argument gives m_n = Φ_{n+3} – 1 (where Φ_{n} is the n-th Fibonacci number: Φ_{1}=1 , and Φ_{2}=1 , and Φ_{n+2}=Φ_{n}+Φ_{n+1}).