If z = 3 − 2j find zz.
If z = 3 − 2j then its conjugate is \bar{z}=3+2 j . Therefore,
\begin{aligned}z z & =(3-2 \mathrm{j})(3+2 \mathrm{j}) \\& =9-6 \mathrm{j}+6 \mathrm{j}-4 \mathrm{j}^2 \\& =9-4 \mathrm{j}^2 \\& =13\end{aligned}
We see that the answer is a real number.