Question 19.7: Perform a DC analysis on the following circuit....
Perform a DC analysis on the following circuit.
Step-by-Step
The circuit shown is similar to that designed in Example 19.6, but with the addition of a decoupling capacitor. As the capacitors may be considered to be open circuit for DC signals, we can analyse the circuit as if they were not present. Therefore, assuming that the gain of the transistor is reasonably high, so that the base current may be neglected, we have
V_{B} = V_{CC} \frac{R_{2}}{R_{1} + R_{2}} = 15.0 \times \frac{13 kΩ}{13 kΩ + 82 kΩ} = 2.05 V \\ V_{E} = V_{B} – V_{BE} = 2.05 – 0.7 = 1.35 V \\ I_{E} = \frac{V_{E}}{R_{E}} = \frac {1.35 V}{1.3 kΩ} = 1.04 mA \\ I_{C} = I_{E} = 1.04 mA \\ V_{o(quiescent)} = V_{CC} – I_{C}R_{C} = 15 V – 1.04 mA \times 5.6 kΩ = 9.2 VRelated Answered Questions
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