Predict which member of each of the following pairs of elements has the greater electronegativity value based on periodic table electronegativity relationships.
a. Cl or Br b. C or O c. Li or K d. Al or N
a. Cl and Br are in the same periodic table group, with Cl being above Br. Therefore Cl is the more electronegative element, as electronegativity decreases going down a group.
b. C and O are in the same periodic table period, with O being farther to the right. Therefore O has the greater electronegativity, as electronegativity increases going across a period.
c. Li and K are in the same group, with Li being two positions above K. Therefore Li is the more electronegative element, as electronegativity decreases going down a group.
d. Al is in Period 3 and N is in Period 2. The element P can be used as a “link” between the two elements. It is in the same period as Al and the same group as N. The periodic table period trend predicts that P is more electronegative than Al and the periodic table group trend predicts that N is more electronegative than P. Therefore, N is more electronegative than Al.