Question 9.12: Repeat problem [9.10] for a plutonium fueled sodium cooled f......

β1 := 0.00021          \operatorname{c1}:=\mathbb{\beta 1}\cdot {\frac{\operatorname{P0}}{(\lambda1\cdot\Lambda)}}     \mathrm{c}2:=\beta 2.{\frac{\mathrm{P}0}{(\lambda2\cdot\Lambda)}}

β2 := 0.00142

β3 := 0.00128             \operatorname{c3}:=\mathbb{\beta 3}\cdot {\frac{\operatorname{P0}}{(\lambda3\cdot\Lambda)}}    \mathrm{c}4:=\beta 4.{\frac{\mathrm{P}0}{(\lambda4\cdot\Lambda)}}

β4 := 0.00257

β5 := 0.00075           \operatorname{c5}:=\mathbb{\beta 5}\cdot {\frac{\operatorname{P0}}{(\lambda5\cdot\Lambda)}}    \mathrm{c}6:=\beta 6.{\frac{\mathrm{P}0}{(\lambda6\cdot\Lambda)}}

β6 := 0.00027

Sample calculations shown for $0.10 below using the stiff differential equations solver Radau (Mathcad) to obtain the vector Y.

\mathrm{Rf}:={\frac{\tau}{\mathrm{MfCf}}}=0.8                             dollars := 0.1

Rf.WCp = 48                                        α1 = -1.8 × 10^{-5}

n := 0 .. 1000