Holooly Plus Logo

Question 6.12: Review Example Analysis 11. Consider again the bracket of Fi......

Review Example Analysis 11. Consider again the bracket of Figure a and as shown again here in Figure a. Let the dimensions/distances shown have the values:

a=2 in,           b=12 in,           c=4 in,                 d=8  in

e=4 in,         h=3/16 in,                    2r= 1/4 in   (a)

Suppose the allowable rivet stress (the tensile stress) is 25,000 psi. Determine the maximum weight (load) W_{max} that the bracket can hold.

6.12a
Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

Recall from Eqs. (k) and (Ρ) of the solution for Example Analysis 11 that the rivet tensile stresses are:

\sigma _{A}=\frac{Wb\left(d+e\right) }{\left(\pi r^{2} \right)\left[\left(d+e\right) ^{2}+e^{2} \right] }    (b)

and

\sigma _{B}=\frac{Wbe }{\left(\pi r^{2} \right)\left[\left(d+e\right) ^{2}+e^{2} \right] }   (c)

By solving these expressions for W we have:

W= \frac{\left(\sigma _{A} \right) \left(\pi r^{2} \right)\left[\left(d+e\right) ^{2}+e^{2} \right]}{\left(b\right)\left(d+e\right) }      (d)

and

W= \frac{\left(\sigma _{B} \right) \left(\pi r^{2} \right)\left[\left(d+e\right) ^{2}+e^{2} \right]}{\left(be\right) }    (e)

Observe in these expressions that the value of W in Eq. (d) is smaller than that in Eq. (e). Therefore, Eq. (d) provides the maximum safe load W_{max}. (Also, by inspection of Figure a we see that rivet A will bear the greater portion of the load.)
By substituting the given data W_{max} then is:

W_{max}=\left(25\right) \left(10^{3}\right)\pi \left\lgroup\frac{1}{8} \right\rgroup ^{2}\left[\left(8+4\right) ^{2}+\left(4\right)^{2} \right]/\left(12\right)\left(8+4\right)

or

W_{max}=1363   lb =1.363  kip     (f)

Comment

Observe in Eq. (d) that the distances a and c, and the thickness dimension t, do not influence the value of the maximum allowable load.

Related Answered Questions