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Question 4.11: Show that R = √x² + y² + z²...

Show that

R={\sqrt{x^{2}+y^{2}+z^{2}}}
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From Figure 4.28

x² +y² = OQ²

From ΔOPQ

OP² = OQ² + PQ²

But OP = R and PQ = z, so

R² = x² +y² +z²

and so

R={\sqrt{x^{2}+y^{2}+z^{2}}}
1

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