Question 7.6: Solve Example 7.4 by Wilson’s proposed procedure with differ......

Solve Example 7.4 by Wilson’s proposed procedure with different data as shown below.

m = 0.065

k = 7.738

ρ = 0.07

F_0=10
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The equation of motion is written as

m \ddot{u}+c \dot{u}+k u=F_0

or  \ddot{u}_t+2 \rho \omega_n \dot{u}+\omega_n^2 u=\frac{F_0}{m} f(t)

\omega_n=\sqrt{\frac{7.738}{0.065}}=10.9  rad / s

\ddot{u}+2 \times 0.07 \times 10.9 \dot{u}+118.81 u=153.8 f(t)

A program for Wilson’s method is written in MATLAB as shown below. The force time curves are shown in Fig. 7.18a. The displacement, velocity and acceleration response are shown in Fig.7.18b, c and d respectively. Wilson’s method is the best to solve problems involving base excitation.

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