The circuit of Fig. 3-17 uses current- (or shunt-) feedback bias. The Si transistor has I_{CEO} ≈ 0, V_{CE\text{sat}} ≈ 0, and h_{FE} = 100. If R_C = 2 kΩ and V_{CC} = 12 \text{V}, size R_F for ideal maximum symmetrical swing (that is, location of the quiescent point such that V_{CEQ} = V_{CC}/2).
Application of KVL to the collector-emitter bias circuit gives
(I_{BQ} + I_{CQ})R_C = V_{CC} – V_{CEQ}
With I_{CQ} = h_{FE}I_{BQ}, this leads to
I_{BQ} = \frac{V_{CC} – V_{CEQ}}{(h_{FE} + 1)R_C} = \frac{12 – 6}{(100 + 1)(2 × 10^{3})} = 29.7 μ\text{A}
Then, by KVL around the transistor terminals,
R_F = \frac{V_{CEQ} – V_{BEQ}}{I_{BQ}} = \frac{6 – 0.7}{29.7 × 10^{-6}} = 178.5 kΩ