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Question 3.SP.13: The circuit of Fig. 3-17 uses current- (or shunt-) feedback ......

The circuit of Fig. 3-17 uses current- (or shunt-) feedback bias.    The Si transistor has I_{CEO} ≈ 0,  V_{CE\text{sat}} ≈ 0, and h_{FE} = 100.    If R_C = 2  kΩ and V_{CC} = 12  \text{V}, size R_F for ideal maximum symmetrical swing (that is, location of the quiescent point such that V_{CEQ} = V_{CC}/2).

3.17
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Application of KVL to the collector-emitter bias circuit gives
(I_{BQ} + I_{CQ})R_C = V_{CC}  –  V_{CEQ}

With I_{CQ} = h_{FE}I_{BQ}, this leads to
I_{BQ} = \frac{V_{CC}  –  V_{CEQ}}{(h_{FE}  +  1)R_C} = \frac{12  –  6}{(100  +  1)(2  ×  10^{3})} =  29.7  μ\text{A}

Then, by KVL around the transistor terminals,
R_F = \frac{V_{CEQ}  –  V_{BEQ}}{I_{BQ}} = \frac{6  –  0.7}{29.7  ×  10^{-6}} =  178.5  kΩ

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