Question 11.SP.7: Water is flowing in a rectangular channel at a velocity of ......
Water is flowing in a rectangular channel at a velocity of 3 fps and depth of 1.0 ft. Neglecting the effect of velocity of approach and employing Eq. (11.27), determine the height of a sharp-crested suppressed weir that must be installed to raise the water depth upstream of the weir to 4 ft .
Step-by-Step
L=\text { length of weir crest }=\text { width of channel }
Eq. (11.27): Q=A V=L y V=L(1)(3)=3.33 L H^{3 / 2}
H^{3 / 2}=\frac{3.0}{3.33}=0.901, \quad H=0.933 \mathrm{ft}
Fig. 11.26: \quad P= height of weir required =4.00-0.933=3.07 \mathrm{ft} \quad
Q \approx \begin{cases}3.32 L H^{3 / 2} & \text { in BG units } \\ 1.83 L H^{3 / 2} & \text { in SI units }\end{cases} (11.27)
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