Chapter 10
Q. 10.14.3
Q. 10.14.3
A fluid motion for which the Reynolds number is small (so that nonlinear terms in velocity are negligible) is known as a creeping flow or Stokes’s flow. For a steady creeping flow of an incompressible viscous fluid under zero body force, show that p is a harmonic function. Deduce that ψ defined by (10.14.19) is a biharmonic function in this case.
\textbf{v}=\psi_{,2}\textbf{e}_{1}-\psi_{,1}\textbf{e}_{2} (10.14.19)
Step-by-Step
Verified Solution
For creeping flow,
\frac{Dv}{Dt}=\frac{\partial \textbf{v}}{\partial t}+(\textbf{v}.\triangledown)\textbf{v}\approx \frac{\partial \textbf{v}}{\partial t} (10.14.27)
Then the Navier-Stokes equation (10.14.6) becomes
v\triangledown^2\textbf{v}-\frac{1}{\rho}\triangledown p+\textbf{b}=\frac{D\textbf{v}}{Dt} (10.14.6)
v\triangledown^2\textbf{v}-\frac{1}{\rho}\triangledown p+\textbf{b}=\frac{\partial\textbf{v}}{\partial t} (10.14.28)
For steady flow with zero body force, this equation reduces to
v\triangledown^2\textbf{v}=\frac{1}{\rho}\triangledown p (10.14.29)
Taking the divergence of this equation and using the equation of continuity div v = 0, we get
\triangledown^2 p=0 (10.14.30)
Thus, p is a harmonic function.
For ψ defined through the relation (10.14.19), we have
v_{1}=ψ_{,2},\ \ v_{2}=-ψ_{,1},\ \ v_{3}=0
Using these in equation (10.14.29), we get
p_{,1}=\rho v\triangledown^2(\psi_{,2});\ \ p_{,2}=-\rho v\triangledown^2(\psi_{,1}) (10.14.31)
From these, we obtain, respectively,
p_{,12}=\rho v\triangledown^2(\psi_{,22});\ \ p_{,21}=-\rho v\triangledown^2(\psi_{,11}) (10.14.32)
so that
v\rho\triangledown^2(\psi_{,11}+\psi_{,22})=-(p_{,21}-p_{,12})=0\ or\ \triangledown^2\psi=0
Thus, ψ is a biharmonic function.