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Question 6.2.1: A nucleus ^AZX decays by alpha decay followed by two success...

A nucleus { }_{Z}^{A} X decays by alpha decay followed by two successive beta decays. Find the atomic and mass numbers of the resulting nucleus.

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The decay equation is

{ }_{Z}^{A} X \rightarrow{ }_{Z}^{A-4} Y+{ }_{2}^{4} \alpha+2{}_{1}^{0} e

so the atomic number is Z and the mass number is A – 4.

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