Question H3.3: A proton (rest energy 938 MeV ) has a total energy of 1170 M...
A proton (rest energy 938 MeV ) has a total energy of 1170 MeV. What is its speed?
Since the total energy is given by E=\gamma m_{0} c^{2} we have that
1170=\frac{938}{\sqrt{1-\frac{v^{2}}{c^{2}}}}\sqrt{1-\frac{v^{2}}{c^{2}}}=0.8017
1-\frac{v^{2}}{c^{2}}=0.6427
\frac{v^{2}}{c^{2}}=0.3573
v = 0.598 c
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