Question A8.17: An amplifier has a power gain of 33 dB. What input power wil...
An amplifier has a power gain of 33 dB. What input power will be required to produce an output power of 11 W?
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Now power gain expressed in decibels will be given by:
10 \log _{10}\left(\frac{P_{\text {out }}}{P_{\text {in }}}\right)Thus = 33 10 \log _{10}\left(\frac{11 W }{P_{\text {in }}}\right)
Dividing both sides by 10 gives:
3.3=\log _{10}\left(\frac{11 W }{P_{\text {in }}}\right)Taking the antilog of both sides gives:
\operatorname{antilog}(3.3)=\frac{11 W }{P_{\text {in }}}1,995=\frac{11 W }{P_{\text {in }}}
from which:
P_{\text {in }}=\frac{11 W }{1,995}=5.5 mWNote that the antilog or ‘inverse log’ function can be found using your calculator. This sometimes appears as a button marked ‘10x ‘ or is obtained by pressing ‘shift’ (to enable the inverse function) and then ‘log’. In any event, you should refer to your calculator’s instruction book for more information on the keystrokes required!
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