Question 2.6: ATTENUATION CONSTANT OF THE COAXIAL LINE In Example 2.1 the ...

ATTENUATION CONSTANT OF THE COAXIAL LINE In Example 2.1 the L, C, R, and G parameters were derived for a lossy coaxial line. Assuming the loss is small, derive the attenuation constant from (2.85a)

\ \alpha \simeq \frac{1}{2} \left(R\sqrt{\frac{C}{L} }+G\sqrt{\frac{L}{C} } \right) =\frac{1}{2} \left(\frac{R}{Z_{0}} +GZ_{0}\right) with the results from Example 2.1.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

From (2.85a),

\ \alpha \simeq \frac{1}{2} \left(R\sqrt{\frac{C}{L} }+G\sqrt{\frac{L}{C} } \right).
Using the results for R and G derived in Example 2.1. gives

\ \alpha=\frac{1}{2} \left[\frac{R_{s}}{\eta \ln b/a}\left(\frac{1}{a}+\frac{1}{b} \right)+\omega \epsilon^{\prime \prime}\eta \right ]

where\ \eta =\sqrt{\mu /\epsilon ^{\prime }} is the intrinsic impedance of the dielectric material filling the coaxial line. In addition,

\ \beta =\omega \sqrt{LC} =\omega \sqrt{\mu \epsilon ^{\prime }} and Z_{0}=\sqrt{L/C} =\left(\eta /2\pi \right) \ln b/a

Related Answered Questions