Question 2.2: BASIC SMITH CHART OPERATIONS A load impedance of 40 + j70 Ω ...

BASIC SMITH CHART OPERATIONS A load impedance of 40 + j70 Ω terminates a 100 Ω transmission line that is 0.3 λ long. Find the reflection coefficient at the load, the reflection coefficient at the input to the line, the input impedance, the standing wave ratio on the line, and the return loss.

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The normalized load impedance is

\ z_{L}=\frac{Z_{L}}{Z_{0}} =0.4+j0.7,

which can be plotted on the Smith chart as shown in Figure 2.11. By using a drawing compass and the voltage coefficient scale printed below the chart, one can read off the reflection coefficient magnitude at the load as |Γ| = 0.59. This same compass setting can then be applied to the standing wave ratio (SWR) scale to read SWR = 3.87 and to the return loss (RL) (in dB) scale to read RL = 4.6 dB.

Now draw a radial line through the load impedance point and read the angle of the reflection coefficient at the load from the outer scale of the chart as 104°.
Now draw an SWR circle through the load impedance point. Reading the reference position of the load on the wavelengths-toward-generator (WTG) scale gives a value of 0.106λ. Moving down the line 0.3 λ toward the generator brings us to 0.406λ on the WTG scale. Drawing a radial line at this position gives the normalized input impedance at the intersection with SWR circle of \ z_{in}= 0.365 −j0.611. Then the input impedance of the line is

\ Z_{in}=Z_{0}z_{in}=36.5 − j61.1 \Omega

The reflection coefficient at the input still has a magnitude of |Γ| = 0.59; the phase is read from the radial line at the phase scale as 248°.

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