Calculate the density of [latex]N_2[/latex] at 260 bar and 15°C by using the compressibility chart.

Pressure, p = 260 bar Temperature, T = 15 + 273 = 288 K Density, ρ = ? For [latex]N_2[/latex] (from Table 8.3) : [latex]p_c=33.94[/latex] bar [latex]T_c=126.2[/latex] K Now [latex]p_r=\frac{p}{p_c}=\frac{260}{33.94}=7.6[/latex] and [latex]T_r=\frac{T}{T_c}=\frac{288}{126.2}=2.28[/latex] From the compressibility chart for [latex]p_r=7.6 \text { and } T_r=2.28, Z \simeq 1.08[/latex] Also [latex]Z=\frac{p v}{R T}=\frac{p}{\rho R T}, \text { where } \rho[/latex] stands for density or [latex]\rho =\frac{p}{Z R T}=\frac{260 \times 10^5}{1.08 \times \frac{8314}{28} \times 288}= 2 8 1 . 5[/latex] kg/m³. Table 8.3. Critical Constants Substance Pressure [latex]\left(p_c\right)[/latex] bar Temperature [latex]\left(T_c\right)[/latex] K Air 37.69 132.5 Argon 48.64 151.0 Carbon dioxide 73.86 304.2 Carbon monoxide 34.96 133.0 Helium 2.29 5.3 Hydrogen 12.97 33.3 Nitrogen 33.94 126.2 Oxygen 50.76 154.8 Water 228.59 647.15 Ethane 48.84 305.5 Ethylene 51.17 282.4 Methane 46.41 191.1 Propane 42.55 370.0

Question 8.13: Calculate the density of N2 at 260 bar and 15°C by using the...

Engineering Thermodynamics

Calculate the density of $N_2$ at 260 bar and 15°C by using the compressibility chart.

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