Question 10.15: Calculating an Enthalpy of Reaction from Bond Energies The r...

Calculating an Enthalpy of Reaction from Bond Energies

The reaction of methane (CH_4) and chlorine produces a mixture of products called chloromethanes. One of these is monochloromethane, CH_3Cl, used in the preparation of silicones. Calculate ΔH for the reaction

CH_4 (g) + Cl_2 (g) \longrightarrow CH_3 Cl(g) + HCl(g)

Analyze
To identify which bonds are broken and formed, it helps to draw structural formulas (or Lewis structures), as in Figure 10-17. To apply expression (10.26) literally, we would break four  \begin{matrix} C-H \end{matrix} bonds and one  \begin{matrix} Cl-Cl \end{matrix} bond and form three  \begin{matrix} C-H \end{matrix} bonds, one  \begin{matrix} C-Cl \end{matrix} bond, and one  \begin{matrix} H-Cl \end{matrix} bond. The net change, however, is the breaking of one  \begin{matrix} C-H \end{matrix} bond and one  \begin{matrix} Cl-Cl \end{matrix} bond, followed by the formation of one  \begin{matrix} C-Cl \end{matrix} bond and one  \begin{matrix} H-Cl \end{matrix} bond.

\Delta H =\Delta H(\text { bond breakage })+\Delta H \text { (bond formation) } \approx \Sigma BE \text { (reactants) } – \Sigma BE \text { (products) }(10.26)

Fig 10.17
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  \begin{array}{r c}\begin{matrix}\text{ΔH  for net bond breakage:}\\\text{ } \\ \text{ } \end{matrix} &\begin{matrix} \text{1 mol } \begin{matrix} C-H \end{matrix}  \text{bonds} & +414  kJ \\ \text{1 mol}  \begin{matrix} Cl-Cl \end{matrix}   \text{bonds} & +243  kJ \\ \hline \text{sum:} & +657  kJ \end{matrix} \end{array}

\begin{array}{r c} \begin{matrix}\text{ΔH  for net bond formation:} \\\text{ } \\ \text{ } \end{matrix}     \begin{matrix} \text{1 mol}  \begin{matrix} C-Cl \end{matrix}  \text{bonds} & -339  kJ \\ \text{1 mol}  \begin{matrix} H-Cl \end{matrix}   \text{bonds} & -431  kJ \\ \hline \text{sum:} & -770  kJ \end{matrix} \end{array}

Enthalpy of reaction:                 ΔH = 657 – 770 = -113 kJ

Assess
A number of terms cancel out because some of the same types of bonds appear in both reactants and products. Such a situation is not uncommon.

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