Question 6.8: Calculating the Heat of Phase Transition from Standard Entha...

Calculating the Heat of Phase Transition from Standard Enthalpies of Formation

Use values of \Delta H_f^{\circ} to calculate the heat of vaporization, \Delta H_{\text {vap }}^{\circ}, of carbon disulfide at 25°C. The vaporization process is

CS_2(l) → CS_2(g)

PROBLEM STRATEGY

The vaporization process can be treated like a chemical reaction, with CS_2(l ) the “reactant” and CS_2(g) the “product.” It is convenient to record the values of \Delta H_f^{\circ} under the formulas in the equation, multiplying them by the coefficients in the equation. You calculate \Delta H_{\text {vap }}^{\circ} by subtracting values for the “reactant” from values for the “product.”

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Here is the equation for the vaporization, with values of \Delta H_f^{\circ} multiplied by coefficients (here, all 1’s).

\underset{1(89.7)}{CS_2(l)}   \longrightarrow  \underset{1(116.9)        (kJ)}{CS_2(g)}

The calculation is

\begin{aligned}\Delta H_{\text {vap }}^{\circ} &=\Sigma  n  \Delta H_f^{\circ} \text { (products) }-\Sigma  m  \Delta H_f^{\circ} \text { (reactants) } \\&=\Delta H_f^{\circ}\left[ CS _2(g)\right]-\Delta H_f^{\circ}\left[ CS _2(l)\right] \\&=(116.9-89.7)  kJ = 2 7 . 2  k J \end{aligned}
example 6.8

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