Question 9.7: Determine the center frequency, Q, and BW for the band-pass ...

Determine the center frequency, Q, and BW for the band-pass output of the statevariable filter in Figure 9–22.

9.22
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For each integrator,

f_c=\frac{1}{2 \pi R_4 C_1}=\frac{1}{2 \pi R_7 C_2}=\frac{1}{2 \pi(1.0 ~\mathrm{k} \Omega)(0.022~ \mu \mathrm{F})}=7.23 ~\mathrm{kHz}

The center frequency is approximately equal to the critical frequencies of
the integrators.

f_0=f_c=7.23~ \mathrm{kHz}

Q=\frac{1}{3}\left(\frac{R_5}{R_6}+1\right)=\frac{1}{3}\left(\frac{100~ \mathrm{k} \Omega}{1.0~ \mathrm{k} \Omega}+1\right)=33.7

B W=\frac{f_0}{Q}=\frac{7.23~ \mathrm{kHz}}{33.7}=\mathbf{2 1 5}~ \mathrm{Hz}

PRACTICE EXERCISE

Determine f_0, Q, and BW for the filter in Figure 9–22 if R_4=R_6=R_7=330 ~\Omega with all other component values the same as shown on the schematic.

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Question: 9.6

Verified Answer:

f_0=\frac{1}{2 \pi C} \sqrt{\frac{R_1+R_3}{...