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## Q. 10.4

Determine the minimum corner radius to make Example 10.1 acceptable (valid) to be used.

## Verified Solution

The cylindrical shell thickness $t_{s}$ must be calculated using Eq. UG27 (c)(1) of the ASME Code, VIII-1:

$t=\frac{P R}{S E-0.6 P}=\frac{1000 \times 24}{15,000 \times 1-0.6 \times 1000}=1.667 \text { in. }$

From Fig. 10.5, sketch b-2, the rule is for

$t_{s}>1.5 \text { in. }$                        $r_{\min }=0.25 t_{s}=0.25(1.667)=0.417 \text { in. }$          ACl