Question 12.4: Determine the total voltage gain of the 3656KG isolation amp...

Determine the total voltage gain of the 3656KG isolation amplifier in Figure 12–12 .

12.12
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The voltage gain of the input stage is

A_{v 1}=\frac{R_{f 1}}{R_{i 1}}+1=\frac{22  \mathrm{k} \Omega}{2.2  \mathrm{k} \Omega}+1=10+1=11

The voltage gain of the output stage is

A_{v 2}=\frac{R_{f 2}}{R_{i 2}}+1=\frac{47  \mathrm{k} \Omega}{10  \mathrm{k} \Omega}+1=4.7+1=5.7

The total voltage gain of the isolation amplifier is

A_{v(t o t)}=A_{v 1} A_{v 2}=(11)(5.7)=62.7

P R A C T I C E EXERCISE

Select resistor values in Figure 12–12 that will produce a total voltage gain of approximately 100.

Related Answered Questions

Question: 12.10

Verified Answer:

First of all, notice that the input voltage in Fig...
Question: 12.9

Verified Answer:

V_{\text {out }}=-(0.025 \mathrm{~V}) \ln \...
Question: 12.8

Verified Answer:

The input voltage and the resistor value are given...
Question: 12.6

Verified Answer:

Calculate the bias current as follows: I_{\...
Question: 12.5

Verified Answer:

I_{\text {out }}=g_m V_{\text {in }}=(1000 ...