Holooly Plus Logo

Question 20.7: Determining the Direction of Spontaneity from Electrode Pote...

Determining the Direction of Spontaneity from Electrode Potentials

Consider the reaction

\mathrm{Zn}^{2+}(a q)+2 \mathrm{Fe}^{2+}(a q) \longrightarrow \mathrm{Zn}(s)+2 \mathrm{Fe}^{3+}(a q)

Does the reaction go spontaneously in the direction indicated, under standard conditions?

PROBLEM STRATEGY

Find the oxidizing agents in the equation; one is on the left side and the other on the right side. Locate these oxidizing agents in a table of electrode potentials. (The oxidizing agent is on the left side of the reduction half-reaction.) The stronger oxidizing agent is the one involved in the half-reaction with the more positive standard electrode potential.

The "Step-by-Step Explanation" refers to a detailed and sequential breakdown of the solution or reasoning behind the answer. This comprehensive explanation walks through each step of the answer, offering you clarity and understanding.
Our explanations are based on the best information we have, but they may not always be right or fit every situation.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Already have an account?

Related Answered Questions