Question 20.9: Draw the output voltage for the RL differentiator in Figure ...
Draw the output voltage for the RL differentiator in Figure 20–43.
First, calculate the time constant.
\tau=\frac{L}{R}=\frac{200 \mu H }{100 \Omega}=2.0 \mu sIn this case, t_{W} = 5\tau, so the output will decay to zero at the end of the pulse.
On the rising edge, the inductor voltage jumps to +5 V and then decays exponentially to zero. It reaches approximately zero at the instant of the falling edge.
On the falling edge of the input, the inductor voltage jumps to -5 V and then goes back to zero. The output waveform is shown in Figure 20–44.
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