Question 2.6.12: Let a mass of 3.0 kg be standing still and a second mass of ...

Physics for the IB Diploma

Let a mass of 3.0 kg be standing still and a second mass of 5.0 kg come along and hit it with velocity 4.0 m s $^{-1}$ . Suppose that the smaller mass moves off with a speed of 3.0 m s $^{-1}$ . What happens to the larger mass? (See Figure 6.10.)

6.10

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Related Answered Questions

Question: 2.6.15

A ball is released from some height above the earth’s surface. Treat the ball and the earth as the entire system under consideration. As the ball falls, is the momentum of the system conserved? ...

Verified Answer:

Yes, because there are no external forces on the s...

Question: 2.6.14

A ball is released from some height above the earth’s surface. Treat the ball as the entire system under consideration. As the ball falls, is the momentum of the system conserved? ...

Verified Answer:

No, because there is an external force acting on t...

Question: 2.6.13

Two masses of 2.0 kg and 4.0 kg are held with a compressed spring between them. If the masses are released, the spring will push them away from each other. If the smaller mass moves off with a speed of 6.0 m s^-1, what is the speed of the other mass? (See Figure 6.11.) ...

Verified Answer:

Here our system consists of the two masses and the...

Question: 2.6.11

A mass of 2.0 kg moves to the right with a speed of 10.0 m s^-1 and a mass of 4.0 kg moves to the left with a speed of 8.0 m s^-1. What is the total momentum of the system? ...

Verified Answer:

P = (2 × 10 - 4 × 8) Ns = -12 N s The minus sign m...

Question: 2.6.10

Two masses of 2.0 kg and 3.0 kg move to the right with speeds of 4.0 m s^-1 and 5.0 m s^-1, respectively. What is the total momentum of the system? ...

Verified Answer:

P = (2 × 4 + 3 × 5) Ns = 23 N s

Question: 2.6.9

A force F varies with time according to F = 4 + 12t, where F is in newtons and t in seconds. The force acts on a block of mass m = 2.00 kg, which is initially at rest on a frictionless horizontal surface. F makes an angle of 30° with the horizontal (see Figure 6.8). When will the force lift the ...

Verified Answer:

The block will leave the table when the normal rea...

Question: 2.6.8

A force of 1000.0 N acts on a body of 40.0 kg initially at rest for a time interval of 0.0500 s. What is the velocity of the mass? ...

Verified Answer:

The impulse is F Δt = 1000 × 0.05 N s = 50.0 N s a...

Question: 2.6.7

The force in example question 6 is assumed to vary with time as shown in Figure 6.7. Deduce the maximum force that acted on the ball. A second, harder, ball of identical mass to the first also bounces off the wall with the same initial and final speed, but since it is harder it stays in contact ...

Verified Answer:

The area under the curve is the total change in th...

Question: 2.6.6

A ball of mass 0.250 kg moves on a frictionless horizontal floor and hits a vertical wall with speed 5.0 m s^-1. The ball rebounds with speed 4.0 m s^-1. If the ball was in contact with the wall for 0.150 s, find the average force that acted on the ball. ...

Verified Answer:

The magnitude of the change in the ball's momentum...

Question: 2.6.5

A helicopter rotor whose length is R = 5.0 m pushes air downwards with a speed v. Assuming that the density of air is constant at ρ = 1.20 kg m^-3 and the mass of the helicopter is 1200 kg, find v. You may assume that the rotor forces the air in a circle of radius R (spanned by the rotor) to move ...

Verified Answer:

The momentum of the air under the rotor is mv, whe...