Question 6.3: Manipulating Thermochemical Equations When 2 mol H2(g) and 1...
Manipulating Thermochemical Equations
When 2 mol H_2(g) and 1 mol O_2(g) react to give liquid water, 572 kJ of heat evolves.
2H_2(g) + O_2(g) → 2H_2O(l ); ΔH = – 572 kJWrite this equation for 1 mol of liquid water. Give the reverse equation, in which 1 mol of liquid water dissociates into hydrogen and oxygen.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Learn more on how we answer questions.
You multiply the coefficients and ΔH by \frac{1}{2} :
H _2(g) + \frac{1}{2} O _2(g) \longrightarrow H _2 O (l) ; \Delta H = -286 kJReversing the equation, you get
H _2 O (l) \longrightarrow H _2(g) + \frac{1}{2} O _2(g) ; \Delta H = +286 kJRelated Answered Questions
Question: 6.9
Verified Answer:
Here is the equation with the \Delta H_{f}^...
Question: 6.7
Verified Answer:
Multiplying Equation 1 by \frac{1}{2}[/late...
Question: 6.8
Verified Answer:
Here is the equation for the vaporization, with va...
Question: 6.6
Verified Answer:
STEP 1 The heat from the graphite sample is
[l...
Question: 6.5
Verified Answer:
You substitute into the equation
q=s \times...
Question: 6.4
Verified Answer:
9.07 \times 10^5 \cancel{g NH _3} \tim...
Question: 6.2
Verified Answer:
You first write the balanced chemical equation.
[l...
Question: 6.1
Verified Answer:
You substitute into the formula E_k = \fra...