Question 11.11: USING BOILING-POINT ELEVATION TO CALCULATE THE MOLALITY OF A...
USING BOILING-POINT ELEVATION TO CALCULATE THE MOLALITY OF A SOLUTION
What is the molality of an aqueous glucose solution if the boiling point of the solution at 1 atm pressure is 101.27 °C? The molal boiling-point-elevation constant for water is given in Table 11.4.
TABLE 11.4 Molal Boiling-Point-Elevation Constants (K_{b}) and Molal Freezing-Point-Depression Constants (K_{f}) for Some Common Substances
Substance K_{b}[(°C · kg)/mol] K_{f}[(°C · kg)/mol] |
Benzene (C_{6}H_{6}) 2.64 5.07 Camphor (C_{10}H_{16}O) 5.95 37.8 Chloroform (CHCl_{3}) 3.63 4.70 Diethyl ether (C_{4}H_{10}O) 2.02 1.79 Ethyl alcohol (C_{2}H_{6}O) 1.22 1.99 Water (H_{2}O) 0.51 1.86 |
STRATEGY
Rearrange the equation for molal boiling-point elevation to solve for m:
where K_{b} = 0.51 (°C · kg)/mol and ΔT_{b} = 101.27 °C – 100.00 °C = 1.27 °C.
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m = \frac{1.27 °C}{0.51\frac{°C · kg}{mol}} = 2.5 \frac{mol}{kg} = 2.5 m
The molality of the solution is 2.5 m.
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