A 120-V 1/4-hp 60-Hz four-pole split-phase induction motor has the following impedances:
\begin{array}{lll}R_1=2.00 \ \Omega & X_1=2.56 \ \Omega & X_M=60.5 \ \Omega \\R_2=2.80 \ \Omega & X_2=2.56 \ \Omega &\end{array}
At a slip of 0.05, the motor’s rotational losses are 51 W. The rotational losses may be assumed constant over the normal operating range of the motor. If the slip is 0.05, find the following quantities for this motor:
(a) Input power
(b) Air-gap power
(c) P_{\text {conv }}
(d) P_{\text {out }}
(e) \tau_{\text {ind }}
(f) \tau_{\text {load }}
(g) Overall motor efficiency
(h) Stator power factor