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Question 20.4: A 200-μH coil has a Q of 40 at 0.5 MHz. Find Re.

A 200-\mu H coil has a Q of 40 at 0.5 MHz. Find R_e.

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R_e=\frac{X_L}{Q}=\frac{2\pi fL}{Q} =\frac{2\pi \times 0.5\times 10^6\times 200\times 10^{-6}}{40} =\frac{628}{40} =15.7 \Omega

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