A 230 V, 50 Hz voltage is applied to the primary of a 4: 1 stepdown transformer used in a bridge rectifier having a load resistance of 1000 X. Assuming the diode to be ideal, calculate (a) dc output voltage, (b) dc power delivered to the load, (c) PIV and (d) output ripple frequency.

Question

A 230 V, 50 Hz voltage is applied to the primary of a 4: 1 stepdown transformer used in a bridge rectifier having a load resistance of [latex]1000 \Omega [/latex]. Assuming the diode to be ideal, calculate (a) dc output voltage, (b) dc power delivered to the load, (c) PIV and (d) output ripple frequency.

Accepted Answer

(a) RMS value of transformer secondary voltage
[latex]V_{rms}=\frac{230}{4}=57.5V[/latex]
The maximum value of secondary voltage
[latex]V_m=\sqrt{2}V_{rms}=\sqrt{2} imes 57.5=81.3V[/latex]
Therefore, dc output voltage,
[latex]V_{dc}=\frac{2V_m}{\pi}=\frac{2 imes 81.3}{\pi}=51.8V\approx 52V[/latex]
(b) dc power delivered to the load,
[latex]P_{dc}=\frac{V_{dc}^2}{R_L}=\frac{{52}^2}{1000}=2.704W[/latex]
(c)[latex]PIV=V_m=81.3V[/latex]
(d)Output ripple frequency[latex]=2f=2 imes 50=100[/latex]Hz

Question 2.14: A 230 V, 50 Hz voltage is applied to the primary of a 4: 1 s...

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