A 30-mA IR is in parallel with another branch current of 40 mA for IC. The applied voltage VA is 72 V. Calculate IT, ZEQ, and θI

Question

A 30-mA [latex]I_R[/latex] is in parallel with another branch current of 40 mA for [latex]I_C[/latex]. The applied voltage [latex]V_A[/latex] is 72 V. Calculate [latex]I_T, Z_{EQ}, and θ_I[/latex]

Accepted Answer

This problem can be calculated in mA units for I and k[latex]\Omega [/latex] for Z without powers of 10.

[latex]I_T=\sqrt{I^2_R+I^2_C}=\sqrt{(30)^2+(40)^2}[/latex]

[latex]=\sqrt{900+1600}=\sqrt{2500}[/latex]

=50 mA

[latex]Z_{EQ}= \frac{V_A}{I_T}=\frac{72 V}{50 mA}[/latex]

[latex]=1.44 k \Omega[/latex]

[latex] an heta _1=\frac{I_C}{I_R}=\frac{40}{30}=1.333[/latex]

[latex]=\arctan (1.333)[/latex]

[latex] heta _1[/latex]=53.1°

Question 17.2: A 30-mA IR is in parallel with another branch current of 40 ...

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