Question 4.1: A new facility is to have 200 employees. A survey of similar...

If the new facility were to have the same number of parking spaces as similar facilities, 100 spaces would be required. Of these 100 spaces, 40 could be for compact automobiles. However, not all drivers of compact cars will park in a compact space. Therefore, only 30 compact spaces will be provided. Begin the layout of the lot using 90^{\circ} double-loaded, twOway traffic because of its efficient use of space to determine if the available lot is adequate. From Figure 4.2, \mathrm{~W} 4 is the required module option. Using the W4 module and Table 4.1, we can obtain the following:

Check to see if the depth of the lot (200 feet) can accommodate a parking layout consisting of two modules of standard cars and one compact module,

189^{\prime}-2^{\prime \prime}<200 feet; therefore, depth requirement \mathrm{OK}

Each compact module row will yield a car capacity based on the width of the lot (180 feet) divided by the width requirement per stall (8 feet) times the rows per module (2).

\left(\frac{180}{8}\right) \times 2=44 potential compact cars

Similarly, each standard module row will yield a car capacity based on the width of the lot (180 feet) divided by the width requirement per stall (8.5 feet) times the number of rows per module (2) times the number of modules (2).

\left(\frac{180}{8.5}\right) \times 2 \times 2=84 potential standard cars

Total possible =44+84=128, which is greater than the required number. Therefore, module configuration (W4) is feasible. A possible alternative of ( 2 rows/modules \times 2 standard modules) + ( 2 rows/module \times 1 compact module) for a total of six rows is a starting point for the layout.

Modifying the layout to account for handicap requirements and circulation reveals the following:

Row 1 will handle all five handicap spaces =5\left(12^{\prime}\right)=60.

The remaining space will be occupied by standard cars:

(180-60) / 8.5=14 spaces.

Row adjusting for two circulation lanes of 15^{\prime} each number 2 will handle

(180-(15 \times 2)) / 8.5=17 spaces.

Rows 3 and 4 will yield the same number of spaces.

Row 5 will have (180-30) / 8=18 spaces.

Row 6 will handle 180 / 8=22 spaces.

See Figure 4.3 for the recommended layout. The assignment of compact, standard, and handicap spaces is as follows:

Note that the module width depends on the aisle width and the stall depth (SD), while the module depth depends on the stall width (SW) and parking width (PW). Of course, both the module width and module depth depend on the parking angle (\theta). In Example 4.1, we assumed the cars are parked at 90^{\circ} . Therefore, the number of stalls along the module depth depended only on stall width (SW). If the cars are parked at an angle, however, as we show in Example 4.2, we need to explicitly specify the stall depth (SD). (The module widths shown in Table 4.1 implicitly account for the stall depth.)