Question 11.17: An RC-coupled amplifier has equal input and output-circuit c...

A_{VH}= \frac{A_{V0} }{1+j(\omega /\omega _{2} )}

\left|A_{VH}\right|= \frac{A_{V0}}{\sqrt{1+j(\omega /\omega _{2} )} }

The g ain at 3 dB cut-off frequency is 1/\sqrt{2} of its mid-frequency gain. Therefore,

A_{VH}(\omega _{H} ) = \frac{A_{V0}}{\sqrt{1+(\omega _{H}/\omega _{2})^{2}} }

Solving for \omega _{H}, we have

\omega _{H}= \omega _{2} = 250 × 10^{3}  rad/s