Question 19.6: Calculate L of a coil that has 15,700 Ω of XL at 12 MHz.

Calculate L of a coil that has 15,700 \Omega of X_L at 12 MHz.

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L=\frac{X_L}{2\pi f}=\frac{1}{2\pi f}\times X_L =\frac{1}{6.28\times 12 \times 10^6} \times 15,700 = 0.0133 \times 10^{–6} \times 15,700

= 208.8 \times 10^{–6} H or 208.8 \mu H

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