Question 3.6: Calculate the probability that an energy state above E F is ...

Calculate the probability that an energy state above E_{F} is occupied by an electron.

Let T=300 \mathrm{~K}. Determine the probability that an energy level 3 k T above the Fermi energy is occupied by an electron.

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From Equation (3.79), we can write

\begin{array}{c} \frac{N(E)}{g(E)}=f_{F}(E)=\frac{1}{1+\exp \left(\frac{E-E_{F}}{k T}\right)} \\ \end{array}     (3.79)

\begin{array}{c}f_{F}(E)=\frac{1}{1+\exp \left(\frac{E-E_{F}}{k T}\right)}=\frac{1}{1+\exp \left(\frac{3 k T}{k T}\right)} \end{array}

which becomes

f_{F}(E)=\frac{1}{1+20.09}=0.0474=4.74 \%

Comment

At energies above E_{F}, the probability of a state being occupied by an electron can become significantly less than unity, or the ratio of electrons to available quantum states can be quite small.

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