Calculate the X_L of a 250-μH coil at (a) 1 MHz and (b) 10 MHz.
Question 19.3: Calculate the XL of a 250-μH coil at (a) 1 MHz and (b) 10 MH...
a. At 1 MHz,
X_L=2\pi fL=6.28\times 1\times 10^6\times 250\times 10^{-6}
=1570\Omega
b. At 10 MHz,
X_L=10 \times 1570=15,700 \Omega
Related Answered Questions
L=\frac{X_L}{2\pi f}=\frac{1}{2\pi f}\times...
L=\frac{X_L}{2\pi f}=\frac{6280}{6.28\times...
f=\frac{1}{2\pi L}\times X_L=\frac{1}{6.28\...
a. For a 10-H L,
X_L=2\pi fL=6.28\times 60\...
X_L=\frac{V_L}{I_L}=\frac{62.8V}{0.01 A}[/l...
X_L=2 \pi fL
=6.28\times 41...