If the machine in Problem C-1 is running as a motor at the rated conditions, what is the maximum torque that can be drawn from its shaft without it slipping poles when the field current is zero?

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Accepted Answer

When the field current is zero, [latex]E_A[/latex] = 0, so

[latex]\begin{aligned}& P=\frac{3 V_\phi E_A}{X_d} \sin \delta+\frac{3 V_\phi^2}{2}\left\lgroup\frac{X_d-X_q}{X_d X_q} ight group \sin 2 \delta \& P=\frac{3(7621)^2}{2}\left\lgroup\frac{0.62-0.40}{(0.62)(0.40)} ight group \sin 2 \delta=14.8 \sin 2 \delta \mathrm{\ MW}\end{aligned}[/latex]

At [latex]\delta=45^{\circ}[/latex], 14,8 MW can be drawn from the motor.

Question C.4: If the machine in Problem C-1 is running as a motor at the r...

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