In Fig. 18-19, calculate the turns ratio [latex]N_P/N_S [/latex]that will produce a reflected primary impedance [latex]Z_P[/latex] of (a) 75 [latex]\Omega[/latex]; (b) 600 [latex]\Omega[/latex]

(a) Use Formula (18-11). [latex]\frac{N_P}{N_S}=\sqrt{\frac{Z_P}{Z_S}}[/latex] [latex]=\sqrt{\frac{75 \Omega}{300 \Omega} }[/latex] [latex]=\sqrt{\frac{1}{4} }[/latex] [latex]=\frac{1}{2} [/latex] (b) [latex] \frac{N_P}{N_S}=\sqrt{\frac{Z_P}{Z_S}}[/latex] [latex]=\sqrt{\frac{600 \Omega}{300 \Omega} }[/latex] [latex]=\sqrt{\frac{2}{1} }[/latex] [latex]=\frac{1.414}{1}[/latex]

Question 18.17: In Fig. 18-19, calculate the turns ratio NP/NS that will pro...

Contemporary Electronics: Fundamentals, Devices, Circuits, and Systems [EXP-36259]

In Fig. 18-19, calculate the turns ratio $N_P/N_S$ that will produce a reflected primary impedance $Z_P$ of (a) 75 $\Omega$ ; (b) 600 $\Omega$

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