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Obtain the output { v }_{ 0 } in the circuit of Fig. 5.94.

Step-by-step

\begin{array}{l}\mathrm{v}_{\mathrm{o}}=-\frac{80}{40}\left(-\frac{80}{20}\right)(0.2)-\frac{80}{20}(0.2) \\=3.2-0.8=\underline{2.4 \mathrm{V}}\end{array}

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