Holooly Plus Logo

Question 5.53: The ordinary difference amplifier for fixed-gain operation i...

The ordinary difference amplifier for fixed-gain operation is shown in Fig. 5.81(a). It is simple and reliable unless gain is made variable. One way of providing gain adjustment without losing simplicity and accuracy is to use the circuit in Fig. 5.81(b). Another way is to use the circuit in Fig. 5.81(c). Show that:

(a) for the circuit in Fig. 5.81(a),

\frac{v_{o}}{v_{i}}=\frac{R_{2}}{R_{1}}

(b) for the circuit in Fig. 5.81(b),

\frac{v_{o}}{v_{i}}=\frac{R_{2}}{R_{1}} \frac{1}{1+\frac{R_{1}}{2 R_{G}}}

(c) for the circuit in Fig. 5.81(c),

\frac{v_{o}}{v_{i}}=\frac{R_{2}}{R_{1}}\left(1+\frac{R_{2}}{2 R_{G}}\right)
The "Step-by-Step Explanation" refers to a detailed and sequential breakdown of the solution or reasoning behind the answer. This comprehensive explanation walks through each step of the answer, offering you clarity and understanding.
Our explanations are based on the best information we have, but they may not always be right or fit every situation.
The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Related Answered Questions