What is the total Z of a 600-Ω R in parallel with a 300-Ω XL? Assume 600 V for the applied voltage.

Question

What is the total Z of a 600- [latex]\Omega [/latex] R in parallel with a 300- [latex]\Omega X_L [/latex]? Assume 600 V for the applied voltage.

Accepted Answer

[latex]I_R=\frac{600 V}{600\Omega}= 1A[/latex]

[latex]I_L=\frac{600 V}{300\Omega}= 2A[/latex]

[latex]I_T=\sqrt{I^{2}_R+I^{2}_L }[/latex]

[latex]=\sqrt{1+4}=\sqrt{5}[/latex]

=2.24 A

Then, dividing the assumed value of 600 V for the applied voltage by the total line current gives

[latex]Z_{EQ}=\frac{V_A}{I_T}=\frac{600 V}{2.24 A}[/latex]

[latex]=268 \Omega[/latex]

Question 20.2: What is the total Z of a 600-Ω R in parallel with a 300-Ω XL...