Design of Machinery 6th. Edition by Robert L. Norton | 9781260113310 | 1260113310 | Holooly

Design of Machine

Design of Machinery

68 SOLVED PROBLEMS

Question: 16.4

Improvement to the Design of Example 16-3 Given: The design of Example 16-3 proved to be dynamically poor. In that example the required position and velocity constraints were applied to the slider motion and the resulting function was transformed by equations relating slider motion to crank ...

Verified Answer:

1 The functions chosen to provide the motions will...

Question: 16.3

Slider-Crank Linkage Driven by a Servomotor to Perform a Forming Operation Given: A slider-crank linkage mechanism (Figure 16-11) has been designed to provide the geometry for a suitable motion of a die in a forming press. The required motion begins from a dwell and moves the slider through a 2-in ...

Verified Answer:

1 The functions chosen to provide the motions defi...

Question: 16.2

Cam-Driven Fourbar Slider With Motion Functions Applied to the Output Link Given: A cam-driven fourbar crank-slider with the geometry shown in Figure 16-3 is driven by a cam with a constant velocity motion program similar to that developed in Example 8-12 and Figure 8-42. The slider is the end ...

Verified Answer:

1 The linkage geometry is the same as shown in Fig...

Question: 16.1

Cam-Driven Fourbar Slider With Motion Functions Applied to the Input Link Given: A cam-driven fourbar crank-slider with the geometry shown in Figure 16-3 is driven by a cam with a constant velocity motion program similar to that developed in Example 8-12 and Figure 8-42. The slider is the end ...

Verified Answer:

1 The equations for the position of the crank-slid...

Question: 11.5

Determining the Energy Variation in a Torque-Time Function. Given: An input torque-time function which varies over its cycle. Figure 11-11 shows the input torque curve from Figure 11-8. The torque is varying during the 360° cycle about its average value. Find: The total energy variation over one ...

Verified Answer:

1 Calculate the average value of the torque-time f...

Question: 11.3

Dynamic Force Analysis of a Fourbar Linkage. (See Figure 11-3) Given: The 5-in-long crank (link 2) shown weighs 1.5 lb. Its CG is at 3 in @ +30° from the line of centers (LRCS). Its mass moment of inertia about its CG is 0.4 lb-in-sec². Its kinematic data are: θ2 deg ω2 rad/sec α2 rad/sec² aG2 ...

Verified Answer:

1 Convert the given weight to proper mass units, i...

Question: 9.8

Determining the Efficiency of an Epicyclic Gear Train.* Find the overall efficiency of the epicyclic train shown in Figure 9-43. The basic efficiency E0 is 0.9928 and the gear tooth numbers are: NA= 82t, NB= 84t, NC = 86t, ND = 82t, NE = 82t, and NF = 84t. Gear A (shaft 2) is fixed to the frame, ...

Verified Answer:

1 Find the basic ratio ρ for the gear train using ...

Question: 9.7

Analyzing Ferguson’s Paradox by the Formula Method. Consider the same Ferguson paradox train as in Example 9-6 which has the following tooth numbers and initial conditions (see Figure 9-37): Sun gear #2 N2 = 100-tooth external gear Sun gear #3 N3 = 99-tooth external gear Sun gear #4 N4 = 101-tooth ...

Verified Answer:

1 We will have to apply equation 9.14 twice, once ...

Question: 9.1

Determining Gear Tooth and Gear Mesh Parameters. Find the gear ratio, circular pitch, base pitch, pitch diameters, pitch radii, center distance, addendum, dedendum, whole depth, clearance, outside diameters, and contact ratio of a gearset with the given parameters. If the center distance is ...

Verified Answer:

1 The gear ratio is found from the tooth numbers o...

Question: 8.9

Designing a Polynomial for an Asymmetrical Rise-Fall Single-Dwell Case. Redefine the specification from Example 8-8 as: rise-fall rise 1 in (25.4 mm) in 45° and fall 1 in (25.4 mm) in 135° over 180° dwell at zero displacement for 180° (low dwell) cam ω 15 rad/sec ...

Verified Answer:

Figure 8-31 shows the minimum set of seven BCs for...

Loading...