The product of [\text{H}_3\text{O}^+]\text{ and [OH}^-] remains constant at 25°C because the value of K_\text{w} is constant at a given temperature. Use K_\text{w} = [\text{H}_3\text{O}^+] [\text{OH}^-] = 1.0 \times 10^{-14}\text{ to solve for [H}_3\text{O}^+].
Calculating [\text{H}_3\text{O}^+] : \\ [\text{H}_3\text{O}^+]=\frac{K_\text{w}}{[\text{OH}^-]} =\frac{1.0\times 10^{-14}}{6.7\times 10^{-2}} =1.4925\times 10^{-13}=1.5\times 10^{-13} \ M
Since [\text{OH}^-] > [\text{H}_3\text{O}^+] , the solution is basic.
Check: The solution is neutral when either species concentration is 1 \times 10^{-7} \ M. Since the problem specifies an [\text{OH}^-] much greater than this, the solution is basic.