Question 21.1: A 35-μF capacitor is connected to a 120-V, 60-Hz line. How m......

The first step is to compute the capacitive reactance. Recall that the value of C in the formula is given in F. This must be changed to the capacitive units being used—in this case, μF:

X_C=\frac{1}{2×3.1416×60×(35×10^{-6})}

X_C=75.788\ Ω

Now that the value of capacitive reactance is known, it can be used like resistance in an Ohm’s law formula. Since capacitive reactance is the current limiting factor, it will replace the value of R:

I=\frac{E}{X_C}

I=\frac{120\ V}{75.788\ Ω}

I=1.583\ A