Question 21.2: A capacitor is connected into a 480-V, 60-Hz circuit. An amm......

The first step is to compute the value of capacitive reactance. Since capacitive reactance, like resistance, limits current flow, it can be substituted for R in an Ohm’s law formula:

X_C=\frac{E}{I}

X_C=\frac{480\ V}{2.6\ A}

X_C=184.615\ Ω

Now that the capacitive reactance of the circuit is known, the value of capacitance can be found:

C=\frac{1}{2πfX_C}

C=\frac{1}{2×3.1416×60\ Hz×184.615\ Ω}

C=\frac{1}{69,598.378}

C=0.000014368\ F=14.368\ μF