Question 20.18: A centrifugal pump running at 1000 rpm. It delivers 100 litr......

Given data: 
Speed of pump               N = 1000 rpm

Discharge           Q=100 \text { litres } / \mathrm{s}=0.1 \mathrm{~m}^3 / \mathrm{s}

Head                            H = 12 m

The specific speed of the pump is obtained from Eq. (20.30) as

N_{S P}={\frac{N{\sqrt{Q}}}{(H)^{3/4}}}            (20.30)

N_s=\frac{N \sqrt{Q}}{H^{3 / 4}}=\frac{1000 \times \sqrt{0.1}}{24^{3 / 4}}=29.16 \text { unit }