A man plans to save $1000 a month for the next 20 years, at 10% per year, compounded monthly. How much money will he have at the end of 20 years?
Equation (2.3), with the appropriate substitutions, gives
F/A = \frac{(1 + i)^n – 1}{i} (2.3) \\\\ F = \$1000\frac{ (1 + 0.10/12)^{(12)(20)} – 1}{0.10/4} = \$1000\frac{6.32807}{0.0083333} = \$759 371.43