Holooly Plus Logo

Question 4.P.9: How much money must be deposited in a savings account each m......

How much money must be deposited in a savings account each month to accumulate $10 000 at the end of 5 years, if the bank pays interest at the rate of 6% per year, compounded (a) monthly? (b) semiannually? (c) quarterly? (d) daily?

Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

In each case use (2.4), with the appropriate substitutions.

A/F  =  (F/A)^{-1}  =  \frac{i}{(1  +  i)^n  –  1}    (2.4)

(a) A  =  \$10  000\frac{0.06112}{(1  +  0.06112)^{(12)(5)}  –  1}  =  \$10  000\frac{0.005}{0.34885}  =  \$143.33 per month

(b) A  =  \$10  000\frac{0.0612}{(1  +  0.0612)^{(2)(5)}  –  1}  =  \$10  000\frac{0.03}{0.34392}  =  \$872.30 every 6 months

or $872.3016 = $145.38 per month.

(c) A  =  \$10  000\frac{0.0614}{(1  +  0.0614)^{(4)(5)}  –  1}  =  \$10  000\frac{0.015}{0.34686}  =  \$432.45 per quarter

or $432.4513 = $144.15 per month.

(d) r  =  \frac{6\%}{12}  =  0.005        \alpha  =  30 \\\\ i  =  \left(1  +  \frac{0.005}{30}\right)^{30}  –  1  =  .0050121 \\\\ A  =  \$10  000\frac{0.0050121}{(1  +  0.0050121)^{(12)(5)}  –  1}  =  \$10  000\frac{0.0050121}{0.34982}  =  \$143.28 per month

Related Answered Questions

Question: 4.P.8

Verified Answer:

Here, r = 10%/12 = 0.00833333 and α = 30; hence by...
Question: 4.P.6

Verified Answer:

F  =  \$1000\frac{(1  +  0.10/4)^{(4)(20)} ...