Question 16.SP.10: A turbine homologous to the turbine of Sample Prob. 16.9 has......

Eq. (16.16): If h does not change, n \propto D^{-1}

Hence: \quad n_{2}=(2 / 1) n_{1}=(2 / 1) 150=300 \mathrm{rpm} \quad

Eq. (16.17): If h does not change, Q \propto D^{2}

Hence: \quad Q_{2}=(1 / 2)^{2} Q_{1}=(1 / 4) 200=50 \mathrm{cfs} \quad

Eq. (16.18): If h does not change, P \propto D^{2}

Hence: \quad P_{2}=(1 / 2)^{2} P_{1}=(1 / 4) 1600=400 \mathrm{hp} \quad

 n \propto h^{1 / 2} / D \quad \text { or } \quad n=K_n h^{1 / 2} / D      (16.16)

Q=K_Q h^{1 / 2} D^2      (16.17)

P=K_p h^{3 / 2} D^2      (16.18 )