Question 16.SP.6: Francis turbine operating at 300 rpm develops a shaft horsep......
Francis turbine operating at 300 rpm develops a shaft horsepower of 1125 hp when the flow is 120cfs. Find the torque transmitted from the flowing water to the shaft.
Step-by-Step
Shaft power =T \omega
\begin{aligned}\frac{T\left(\frac{2 \pi n}{60}\right)}{550} & =1125 \mathrm{hp}, \quad \text { where } n=330 \mathrm{rpm} \end{aligned}
So T=\frac{550 \times 1125}{\left(\frac{2 \pi}{60}\right) 300}=19,700 \mathrm{ft} \cdot \mathrm{lb}
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